1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
|
"""Bisection algorithms."""
def insort_right(a, x, lo=0, hi=None, *, key=None):
"""Insert item x in list a, and keep it sorted assuming a is sorted.
If x is already in a, insert it to the right of the rightmost x.
Optional args lo (default 0) and hi (default len(a)) bound the
slice of a to be searched.
"""
if key is None:
lo = bisect_right(a, x, lo, hi)
else:
lo = bisect_right(a, key(x), lo, hi, key=key)
a.insert(lo, x)
def bisect_right(a, x, lo=0, hi=None, *, key=None):
"""Return the index where to insert item x in list a, assuming a is sorted.
The return value i is such that all e in a[:i] have e <= x, and all e in
a[i:] have e > x. So if x already appears in the list, a.insert(i, x) will
insert just after the rightmost x already there.
Optional args lo (default 0) and hi (default len(a)) bound the
slice of a to be searched.
"""
if lo < 0:
raise ValueError('lo must be non-negative')
if hi is None:
hi = len(a)
# Note, the comparison uses "<" to match the
# __lt__() logic in list.sort() and in heapq.
if key is None:
while lo < hi:
mid = (lo + hi) // 2
if x < a[mid]:
hi = mid
else:
lo = mid + 1
else:
while lo < hi:
mid = (lo + hi) // 2
if x < key(a[mid]):
hi = mid
else:
lo = mid + 1
return lo
def insort_left(a, x, lo=0, hi=None, *, key=None):
"""Insert item x in list a, and keep it sorted assuming a is sorted.
If x is already in a, insert it to the left of the leftmost x.
Optional args lo (default 0) and hi (default len(a)) bound the
slice of a to be searched.
"""
if key is None:
lo = bisect_left(a, x, lo, hi)
else:
lo = bisect_left(a, key(x), lo, hi, key=key)
a.insert(lo, x)
def bisect_left(a, x, lo=0, hi=None, *, key=None):
"""Return the index where to insert item x in list a, assuming a is sorted.
The return value i is such that all e in a[:i] have e < x, and all e in
a[i:] have e >= x. So if x already appears in the list, a.insert(i, x) will
insert just before the leftmost x already there.
Optional args lo (default 0) and hi (default len(a)) bound the
slice of a to be searched.
"""
if lo < 0:
raise ValueError('lo must be non-negative')
if hi is None:
hi = len(a)
# Note, the comparison uses "<" to match the
# __lt__() logic in list.sort() and in heapq.
if key is None:
while lo < hi:
mid = (lo + hi) // 2
if a[mid] < x:
lo = mid + 1
else:
hi = mid
else:
while lo < hi:
mid = (lo + hi) // 2
if key(a[mid]) < x:
lo = mid + 1
else:
hi = mid
return lo
# Overwrite above definitions with a fast C implementation
try:
from _bisect import *
except ImportError:
pass
# Create aliases
bisect = bisect_right
insort = insort_right
|